PV=kT
since T is constant, kT is constant, and so is PV.
so, you want V such that
0.5*V = 0.8*3.5
since T is constant, kT is constant, and so is PV.
so, you want V such that
0.5*V = 0.8*3.5
Now, back to your question. We can use Boyle's Law to solve this. Boyle's Law states that the volume of a gas is inversely proportional to its pressure, assuming the temperature remains constant.
So, we can set up a proportion:
V1/P1 = V2/P2
Where V1 is the initial volume (3.5 L), P1 is the initial pressure (0.8 atm), V2 is the final volume (which we need to find), and P2 is the final pressure (0.5 atm).
Plugging in the values:
3.5 L / 0.8 atm = V2 / 0.5 atm
Cross-multiplying:
0.8 atm * V2 = 3.5 L * 0.5 atm
Dividing both sides by 0.8 atm:
V2 = (3.5 L * 0.5 atm) / 0.8 atm
V2 = 2.1875 L
So, if the pressure was 0.5 atm, the volume of the gas would be approximately 2.1875 L. But be careful not to "inflate" this answer!
The formula for Boyle's Law is:
P1 * V1 = P2 * V2
Where:
P1 = Initial pressure
V1 = Initial volume
P2 = Final pressure
V2 = Final volume
Let's plug in the given values:
P1 = 0.8 atm
V1 = 3.5 L
P2 = 0.5 atm
Using the formula, we can rearrange it to solve for V2:
V2 = (P1 * V1) / P2
Now, substitute the values:
V2 = (0.8 atm * 3.5 L) / 0.5 atm
V2 = 2.8 L
Therefore, the final volume of the gas would be 2.8 L if the pressure was 0.5 atm while the temperature remains constant.
Boyle's Law equation:
P1 * V1 = P2 * V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure (0.5 atm in this case)
V2 = final volume (unknown)
First, let's plug in the given values:
P1 = 0.8 atm
V1 = 3.5 L
P2 = 0.5 atm
Now we can rearrange the equation to solve for V2:
V2 = (P1 * V1) / P2
Substituting the values:
V2 = (0.8 atm * 3.5 L) / 0.5 atm
V2 = 2.8 L
Therefore, if the pressure of the gas is reduced to 0.5 atm while keeping the temperature constant, the volume of the gas would be 2.8 L.