Find dy/dx

x^2 + xy − y^3 = xy^2

Steve Steve answered
6 years ago

x^2 + xy − y^3 = xy^2

2x + y + xy' - 3y^2y' = y^2 + 2xyy'
y'(x-3y^2-2xy) = y^2-2x-y

y' = (y^2-2x-y) / (x-3y^2-2xy)

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