Question

45.0 grams of water vapor is cooled from 150 to 101 degrees celsius. How much heat energy was lost?

heat= mass*specificheatsteam*deltaTemp

Answer 1

[AI-generated answer — Explain Bot]

To calculate the amount of heat energy lost, you need to use the specific heat capacity of water vapor. The specific heat capacity of water vapor is approximately 2.03 J/g·°C.

First, calculate the change in temperature (delta T):
delta T = final temperature - initial temperature
delta T = 101°C -150°C
delta T = -49°C

The negative sign indicates a temperature decrease.

Next, calculate the heat energy lost using the formula:

heat = mass * specific heat * delta T

Given:
mass = 45.0 grams
specific heat = 2.03 J/g·°C
delta T = -49°C

heat = 45.0 g * 2.03 J/g·°C * -49°C

Now, simply multiply the values together:

heat = -4452.15 J

The heat energy lost is approximately -4452.15 Joules. The negative sign indicates that heat was lost.