which ordered pair is a solution of the inequality y≥4x - 5
(3,4)
(2,1)
(3,0)
(1,1)
1.D
2.C
3.C
4.D
5.B
For x = 3 and y = 4
4 x - 5 = 4 ∙ 3 - 5 = 12 - 5 = 7
3 < 7
y < 4 x - 5
For x = 2 and y = 1
4 x - 5 = 4 ∙ 2 - 5 = 8 - 5 = 3
1 < 3
y < 4 x - 5
For x = 3 and y = 0
4 x - 5 = 4 ∙ 3 - 5 = 12 - 5 = 7
0 < 7
y < 4 x - 5
For x = 1 and y = 1
4 x - 5 = 4 ∙ 1 - 5 = 4 - 5 = -1
1 > - 1
y > 4 x - 5
Ordered pair is ( 1 , 1 )
Algebra 1 A, Part 2
Systems of equations and inequalities
Unit 3, Lesson 6
1.) D
2.) C
3.) C
4.) D
5.) B
Blank got me a 2/5.
I got 2/5 Using your Answers And would have Gotten 100% Using Ethan's
@blank i got a 100% with ethan
1. C
2. A
3. C
4. D
5. D
i got a 2/5 using Ethans answers.
bsbx
ethans is wrong 😐 got me a 2/5
Blank is CORRECT *IF* you are looking for the answers to Algebra 1, Unit 7, Lesson 5, (Systems of equations and inequalities, linear inqualities) quick check. Blank is correct if you are in connexus and you are NOT in honors.
Here are the answers for Unit 8 Lesson 5 ;-;
1. (1,0)
2. 4
3. I
4. (1,1)
5. y > -5x + 3