Benzene has a heat of vaporization of 30.72kj/mol and a normal boiling point of 80.1 C . At what temperature does benzene boil when the external pressure is 445 ? This is how I am solving this problem, but when I enter the answer it says im wrong. Can someone help with the math. Thanks
ln(445/760)= (30720/8.314)*(1/80 - 1/T2)