
b
a
b
c
a
b
b
c
d
c
we didn't start the fire, it was always burning since the worlds been turning!

Crazy and haha are correct, it is 100% accurate. Remember, it's not cheating if you're not caught!

crazy’s right 100%

To ease people who dont feel comfortable with just letters:
1) B. 1,3,9
2) A. 1,2,3,6,⅓,⅔
3) B. i, 78i
4) C. 2i, _10^½
5) A. No positive real roots; Two or no
negative real roots
6) B. Two or no positive real roots; One
negative real root
7) B. Two or no positive real roots; One
negative real root
8) C. 5/2, ⅓
9) D. ⅔±(11/3i)^½
10) C. Complex solutions must appear
in conjugate pairs; Having and odd
number of them is impossible

September 2021: Crazy La Paint is still right, just for anybody who’s still here, you’ll still get 100%

as of september 2021 crazy la paint is still 100% right :)

what's funny to me is that the questions and answers haven't changed in the 3 years since this was posted

Thank you Crazy!

Thanks

A friend tells you that he has a cubic equation with exactly three complex roots. Determine which explanation best explains why this is impossible
Actually, this is quite possible.
However, if you have an equation with only real coefficients, it is impossible because the complex roots must occur in conjugate pairs. So, and odd number of complex roots cannot occur.

^^^^All correct!!! 100%

Thanks crazy la paint it was a 100%

I istg I just saw mr D'arby on an English post...

If you've got 11 questions the answer for the last one is B. Sometimes true.

aiko is correct for all counts. thanks

aiko is right

This looks like an assignment.
The usual procedure is that you do and show some of your work, then indicate where you are encountering difficulties.
I will do the first one for you.
X^3+2x9=0
let f(x) = X^3+2x9=0
since you rational factors only, consider only factors of 9
and try them
f(1) = 1 + 2  9 ≠ 0 , I really don't care what it is, all I care about is the zero
f(1) ≠0
f(3) = 27 + 6  9 ≠ 0
f(3) = 27  6  9 ≠ 0
f(±9) ≠ 0
there are no rational roots
btw, the 2nd one has no rational roots as well
some of these are nasty equations:
e.g. p(x) = 6x^413x^3+13x^239x15
took a while to factor it, copped out and used Wolfram:
http://www.wolframalpha.com/input/?i=6x%5E413x%5E3%2B13x%5E239x15%3D0