do you mean each side is enlarged by 300%?
If so, then the perimeter is also enlarged by 300%
If so, then the perimeter is also enlarged by 300%
So 10 height and 3 the width
To enlarge a rectangle by a certain percentage, we multiply each dimension of the rectangle by (1 + (percentage/100)). In this case, we need to multiply both the length and width of the original rectangle by 1 + (300/100) = 1 + 3 = 4.
So, the dimensions of the enlarged rectangle are:
Length = 10 y * 4 = 40 y
Width = 11 * 4 = 44
Now, let's calculate the perimeters of both the original and the enlarged rectangles.
Perimeter of the original rectangle:
P1 = 2 * (Length + Width)
P1 = 2 * (10 y + 11)
P1 = 2 * 21 y
P1 = 42 y
Perimeter of the enlarged rectangle:
P2 = 2 * (Enlarged Length + Enlarged Width)
P2 = 2 * (40 y + 44)
P2 = 2 * 84
P2 = 168
We can see that the new perimeter, P2, is greater than the original perimeter, P1. Therefore, the new perimeter is larger than the original perimeter after enlarging the rectangle by 300%.