Question

A sailboat starts from rest and accelerates at a rate of 0.18 m/s2 over a distance of 494 m.

(a) Find the magnitude of the boat's final velocity.
(b) Find the time it takes the boat to travel this distance.

Answer 1

any physics teacher can help me ??????

Answer 2

A car starts from rest and travels for 4.1 s with a uniform acceleration of +1.4 m/s2. The driver then applies the brakes, causing a uniform acceleration of -1.8 m/s2. The breaks are applied for 1.80 s.

Answer 3

Vf^2=2*acceleration*distance

distance=1/2 a*t^2 solve for time t.

Answer 4

1. V^2 = Vo^2 + 2a*d.

a. V^2 = 0 + 0.36*494, V = ?.
b. d = 0.5a*t^2.
494 = 0.5*0.18*t^2. t = ?.

2. V = Vo + a*t = 0 + 1.4*4.1 = 5.74 m/s.

V^2 = Vo^2 + 2a*d.
0 = (5.74)^2 - 3.6d. d = ?.

Answer 5

87.01

Answer 6

[AI-generated answer — Explain Bot]

To find the answers to these questions, we can use the equations of motion. The equations we need to use are:

1. v = u + at
2. s = ut + (1/2)at^2
3. v^2 = u^2 + 2as

where:
v is the final velocity
u is the initial velocity (in this case, it is 0 m/s since the sailboat starts from rest)
a is the acceleration (0.18 m/s^2)
t is the time taken
s is the distance traveled (494 m)

(a) To find the magnitude of the boat's final velocity, we need to use equation 1. Since the initial velocity u is 0, the equation simplifies to:

v = at

Substituting the values, we have:

v = 0.18 m/s^2 * t

(b) To find the time it takes for the boat to travel the given distance, we need to use equation 2, which is:

s = ut + (1/2)at^2

Rearranging the equation, we get:

(1/2)at^2 + ut - s = 0

This is a quadratic equation in terms of t. We can solve this equation using the quadratic formula:

t = (-u ± √(u^2 + 2as)) / a

Substituting the values, we have:

t = (-0 ± √(0^2 + 2 * 0.18 * 494)) / 0.18

Simplifying the equation will give us the answer for part (b).

Now, let's solve these equations to find the final velocity and time taken.