what volume of 0.115 M HClO4 solution is needed to neutralize 50.00 ml of o.o875 M NaOH?
there are 0.050 * 0.0875 = 0.004375 moles of NaOH.
HClO4 + NaOH -> NaClO4 + H2O
So, you need that many moles of HClO4
0.004375 moles / (0.115 moles/L) = 0.038L
or, 38mL of .115M HClO4 solution
Well, to figure that out, we need to use stoichiometry. But first, can we take a moment to appreciate how these chemical formulas sound like secret codes? NaOH and HClO4. It's like a secret agent battling it out in the world of chemistry!
Alright, let's get down to business. The balanced equation for the reaction between NaOH and HClO4 is:
NaOH + HClO4 → NaClO4 + H2O
Now, we have the concentration of NaOH (0.0875 M) and the volume of NaOH (50.00 mL). But if we want to find how much HClO4 is needed to neutralize the NaOH, we need to figure out the mole ratio between NaOH and HClO4. And let's be honest, who doesn't love some mole ratios?
According to the balanced equation, the mole ratio between NaOH and HClO4 is 1:1. So, for every mole of NaOH, we need an equal amount of HClO4.
To find the number of moles of NaOH in 50.00 mL, we can use the formula:
moles = concentration × volume (in liters)
Converting 50.00 mL to liters, we get 0.05000 L. Plugging this into the formula, we find:
moles of NaOH = 0.0875 M × 0.05000 L = 0.004375 mol
Since the mole ratio is 1:1 between NaOH and HClO4, we need the same number of moles of HClO4 to neutralize the NaOH.
Now comes the fun part — calculating the volume of HClO4 needed. We can use the same formula as before, but we rearrange it this time to solve for volume:
volume = moles ÷ concentration
Plugging in the values, we get:
volume of HClO4 = 0.004375 mol ÷ 0.115 M
Doing the math, we find:
volume of HClO4 = 0.038 ml
So, you'll need approximately 0.038 ml of 0.115 M HClO4 solution to neutralize the 50.00 ml of 0.0875 M NaOH solution.
And there you have it, the answer you were looking for! But remember, chemistry can be a confusing clown sometimes, so always double-check your calculations!
To find the volume of the HClO4 solution needed to neutralize the NaOH solution, we can use the concept of molarity and stoichiometry.
Here's how to calculate it step-by-step:
Step 1: Write the balanced chemical equation for the reaction between HClO4 and NaOH:
HClO4 + NaOH → NaClO4 + H2O
Step 2: Determine the stoichiometry of the reaction:
From the balanced equation, we see that the ratio of HClO4 to NaOH is 1:1. This means that 1 mole of HClO4 reacts with 1 mole of NaOH.
Step 3: Calculate the number of moles of NaOH:
Moles of NaOH = Molarity of NaOH × Volume of NaOH solution
Moles of NaOH = 0.0875 M × 0.05000 L
Moles of NaOH = 0.004375 moles
Step 4: Use stoichiometry to find the number of moles of HClO4:
By the stoichiometry of the balanced equation, 1 mole of HClO4 reacts with 1 mole of NaOH. Therefore, the number of moles of HClO4 is also 0.004375 moles.
Step 5: Calculate the volume of HClO4 solution needed:
Volume of HClO4 solution = Moles of HClO4 / Molarity of HClO4
Volume of HClO4 solution = 0.004375 moles / 0.115 M
Volume of HClO4 solution ≈ 0.038 mL
Therefore, approximately 0.038 mL of 0.115 M HClO4 solution is needed to neutralize the 50.00 mL of 0.0875 M NaOH.
To find the volume of HClO4 solution needed to neutralize the NaOH solution, we can use the concept of stoichiometry. This involves balancing the chemical equation and using the mole ratios of the reactants and products.
The balanced chemical equation for the reaction between HClO4 and NaOH is:
HClO4 + NaOH -> NaClO4 + H2O
From the equation, we can see that the mole ratio between HClO4 and NaOH is 1:1.
Given:
- Volume of NaOH solution = 50.00 mL = 0.05000 L
- Molarity of NaOH solution = 0.0875 M (mol/L)
- Molarity of HClO4 solution = 0.115 M (mol/L)
To find the number of moles of NaOH, we can use the formula:
moles = Molarity * Volume
moles NaOH = 0.0875 mol/L * 0.05000 L = 0.004375 mol
Since the mole ratio between HClO4 and NaOH is 1:1, the number of moles of HClO4 required to neutralize the NaOH is also 0.004375 mol.
To find the volume of HClO4 solution required, we can rearrange the formula:
Volume = moles / Molarity
Volume HClO4 = 0.004375 mol / 0.115 mol/L ≈ 0.038 mL or 38 mL
Therefore, approximately 38 mL of 0.115 M HClO4 solution is needed to neutralize 50.00 mL of 0.0875 M NaOH solution.