A man gains 20% by selling apples at a certain price.if he sells it at Rs 1.2 higher than the previous price he gains 40%. Find the original cost price
Let's assume the original cost price of the apples is "x" rupees.
According to the given information:
When the apples are sold at the original price, the man gains 20%.
So, the selling price at the original price is (x + 20% of x) = x + 0.2x = 1.2x.
Now, it is given that if the apples are sold at Rs 1.2 higher than the previous price, the man gains 40%.
So, the new selling price is (1.2x + 40% of 1.2x) = 1.2x + 0.4 * 1.2x = 1.2x + 0.48x = 1.68x.
According to the information given, we have:
1.68x = 1.2x
Subtracting 1.2x from both sides:
1.68x - 1.2x = 1.2x - 1.2x
0.48x = 0
This implies x = 0 / 0.48
Hence, the original cost price of the apples is 0 rupees.
To find the original cost price, let's assume the original cost price of the apples is "x" rupees.
According to the given information, when the man sells the apples at a certain price, he gains 20%. This means he sells the apples for 120% of the cost price.
So, the selling price after a 20% gain would be 1.2 times the original cost price (x):
Selling Price = 1.2x
In the second scenario, when the man sells the apples at a price that is 1.2 rupees higher than the previous price, he gains 40%. This means he sells the apples for 140% of the cost price.
So, the selling price after a 40% gain would be 1.4 times the original cost price (x):
Selling Price = 1.4x
Now, we can set up an equation to find the original cost price:
1.2x = 1.4x - 1.2
Simplifying the equation:
1.2x - 1.4x = -1.2
-0.2x = -1.2
Dividing both sides of the equation by -0.2:
x = -1.2 / -0.2
x = 6
Therefore, the original cost price of the apples is 6 rupees.
c*1.2 + 1.2 = c*1.4
c = 6