Let n be the amount Ronnel started with. After he spent 1/5, he had 4/5 left. Similarly, he had 3/4ths of that amount after more spending. All told, he had:
(4/5 x 3/4)n=360
(3/5)n=360
n=360/(3/5)=600 to start with
☺☺☺☺
(4/5 x 3/4)n=360
(3/5)n=360
n=360/(3/5)=600 to start with
☺☺☺☺
Then let be straight forward i.e
1/5x+(1/4×4/5)x=1
Then.1/5x+1/5x=1
Then.2/5x=1
We can say 1-2/5x= 3/5x
Then 3/5x=360
Now x=360×5÷3=600
Let's start with the ₱360.00 left in his wallet. This represents 3/4 of the remaining money after buying the magazine.
To find the total remaining money, we can divide ₱360.00 by 3/4:
₱360.00 ÷ (3/4) = ₱360.00 × (4/3) = ₱480.00
So, Ronnel had ₱480.00 left after buying the magazine. This ₱480.00 represents 4/5 of his money at that point.
To find the total money Ronnel had before buying the magazine, we can divide ₱480.00 by 4/5:
₱480.00 ÷ (4/5) = ₱480.00 × (5/4) = ₱600.00
Therefore, Ronnel had ₱600.00 at first. I hope this doesn't make your head spin like a merry-go-round!
Step 1: Ronnel spent 1/5 of his money to buy food, leaving him with 4/5 of his money.
Amount remaining after buying food = (4/5) * x
Step 2: Ronnel spent 1/4 of the remaining money to buy a magazine, leaving him with 3/4 of the remaining money.
Amount remaining after buying magazine = (3/4) * (4/5) * x
According to the given information, Ronnel had ₱360.00 left in his wallet after buying the magazine.
So, (3/4) * (4/5) * x = ₱360.00
Simplifying, (3/5) * x = ₱360.00
Multiplying both sides by 5/3 to isolate x, we get
x = (₱360.00 * 5) / 3
x = ₱600.00
Therefore, Ronnel had ₱600.00 at first.
Let's start with the money he had left in his wallet, which is ₱360.00.
Ronnel spent 1/4 of the remaining money on a magazine, so we need to find the money he had before buying the magazine. Let's assign a variable to represent this amount.
Let's call the money he had before buying the magazine as "M2".
We know that Ronnel had ₱360.00 left after buying the magazine, so we can set up the equation:
M2 - (1/4)M2 = ₱360.00
Now, let's simplify the equation:
(3/4)M2 = ₱360.00
To isolate M2, we can multiply both sides of the equation by the reciprocal of (3/4), which is (4/3):
M2 = (₱360.00) * (4/3)
M2 = ₱480.00
Now we know that Ronnel had ₱480 before buying the magazine.
Next, Ronnel spent 1/5 of his money on food. We need to find the money he had before buying the food. Let's assign a variable to represent this amount.
Let's call the money he had before buying the food as "M1".
We know that Ronnel had ₱480.00 before buying the magazine, so we can set up the equation:
M1 - (1/5)M1 = ₱480.00
Now, let's simplify the equation:
(4/5)M1 = ₱480.00
To isolate M1, we can multiply both sides of the equation by the reciprocal of (4/5), which is (5/4):
M1 = (₱480.00) * (5/4)
M1 = ₱600.00
Therefore, Ronnel had ₱600.00 in his wallet at first.