Question

Given: ABCD is a rhombus,

AB = 6, and m∠A=60°
Find: The height.

Answer 1

AD is also 6, so the height is 6 sin60°

Answer 2

ur wrong

Answer 3

6root6

Answer 4

The height is 3 times the square root of 3 or square root 27 simplified

Answer 5

3 root 3 is the correct answer

Answer 6

the height is 5.2 units

Answer 7

the answer is 3 root 3

u see using the opposite leg from 60 degree thereom and also using the pythagorean thrm u should get 3 root 3 to be the answer.
ps. ur welcome ppl

Answer 8

Height is 5.20 units. This is because the area of the rhombus divided by the base of the rhombus is equal to the height of said rhombus.

Answer 9

[AI-generated answer — Explain Bot]

To find the height of the rhombus, you need to use the formula for the area of a rhombus. The formula is:

Area = (diagonal1 * diagonal2) / 2

In a rhombus, the diagonals are perpendicular bisectors of each other, which means they intersect at a right angle.

First, let's find the length of the diagonals using the given information. Since we know AB = 6, we can find the length of the diagonals using the properties of a rhombus.

In a rhombus, the diagonals are congruent. Let's call the length of both diagonals d.

Since m∠A = 60°, we can see that triangle ABD is a 30-60-90 triangle.

In a 30-60-90 triangle, the lengths of the sides are proportional to the ratio 1 : √3 : 2.

So, AB / BD = 1 / √3.

Simplifying, we get BD = AB√3 = 6√3.

Since the diagonals are congruent, we have: d = 2 * BD = 12√3.

Now, let's substitute the values in the formula for the area of the rhombus:

Area = (diagonal1 * diagonal2) / 2.

Area = (12√3 * 12√3) / 2 = (144 * 3) / 2 = 432 / 2 = 216.

The area of the rhombus is 216.

To find the height of the rhombus, we can divide the area by the length of one side.

Height = Area / side length.

Height = 216 / 6 = 36.

Therefore, the height of the rhombus is 36 units.