v = 1/3 Bh, so
100 = 1/3 B * 12
Now solve for B, the area of the square base, and then the side is easy
100 = 1/3 B * 12
Now solve for B, the area of the square base, and then the side is easy
100= 1/3 b 12
100 . 3 : 12 = b
25 cm = b [ base ]
5cm = lenght of the base
Volume = (1/3) * base area * height
In this case, the volume is given as 100 cm^3, and the height is given as 12 cm:
100 = (1/3) * base area * 12
To solve for the base area, we can rearrange the formula:
base area = (3 * volume) / height
Now we can substitute the given values into the formula:
base area = (3 * 100) / 12
base area = 300 / 12
base area = 25 cm^2
Since the base of a square is a square itself, the length of each side of the square base is the square root of the base area. Therefore, we can find the length of the square base by taking the square root of 25:
Length of square base = √25
Length of square base = 5 cm
So, the length of the square base of the pyramid is 5 cm.