drop an altitude to the center of the base. Then, looking from the side, you will see that
3^2 + 4^2 = s^2
Pyramid base = 6cm
Height = 4cm
A.) 7cm*
B.) 5cm
C.) 9cm
D.) 8cm
Ca n someone please check this?
3^2 + 4^2 = s^2
get a grip, guy!
36 + 16 = 52
Square root of 52 is 7.
Don't you know a 3-4-5 right triangle?
In this case, the height of the pyramid is given as 4cm and the base is given as 6cm.
We can divide the base in half to get 6/2 = 3cm.
Using the Pythagorean theorem, we can write the equation as follows:
Slant height^2 = height^2 + (1/2 * base)^2
Substituting the given values into the equation, we have:
Slant height^2 = 4^2 + 3^2
Slant height^2 = 16 + 9
Slant height^2 = 25
Taking the square root of both sides, we get:
Slant height = √25
Slant height = 5
Therefore, the slant height of the pyramid is 5 cm.
The closest option to the calculated value is B.) 5cm. So, it seems that the answer is correct.