If the tree's height is x meters, the broken tree forms a right triangle with sides 12/25 x and 10. The hypotenuse is 13/25 x.
10^2 + (.48x)^2 = (.52x)^2
Now just solve for x.
10^2 + (.48x)^2 = (.52x)^2
Now just solve for x.
We are given that the tops of the broken tree touched the ground at a distance of 10 m from its base. This means that the remaining part of the tree, after it broke, has a height of H - 10 m.
We are also given that the height of the point where the tree broke from the ground is 12/25 of the total height of the tree. Therefore, the height of the broken part is (12/25)H.
Now, since the broken part and the remaining part of the tree together make up the total height (H), we can write the equation:
(H - 10) + (12/25)H = H
Simplifying this equation, we get:
25(H - 10) + 12H = 25H
25H - 250 + 12H = 25H
37H - 250 = 25H
37H - 25H = 250
12H = 250
H = 250 / 12
H = 20.83
Therefore, the height of the tree is approximately 20.83 meters.