All students in Peter's class have $1.05, consisting of nickels and/or dimes and/or quarters. Each student has a different combination of coins, and all possible combinations of coins are included. What is the probability that Peter is unable to give his friend Jenny change for $1.00?
total amount of possibilities: 31 (Ok here goes nothing)
Q D N X = not able to give change
4 0 1 ✓ ✓ = able to give change
3 3 0X
3 2 2✓
3 1 4✓
3 0 6✓
2 5 1✓
2 4 3✓
2 3 5✓
2 2 7✓
2 1 9✓
2 0 11✓
1 8 0X
1 7 2✓
1 6 4✓
1 5 6✓
1 4 8✓
1 3 10✓
1 2 12✓
1 1 14✓
1 0 16✓
0 10 1✓
0 9 3✓
0 8 5✓
0 7 7✓
0 6 9✓ (haha 69 funny number)
0 5 11✓
0 4 13✓
0 3 15✓
0 2 17✓
0 1 19✓
0 0 21✓
R U IN SPIRIT OF MATH GUY ABOVE ME
So what is the answer???
What’s the answer?! Some of us really need help on this!!! Our LIVES depend on it
BRO U HAVE NO IDEA HOW MUCH UVE SAVED ME.
IM GOING TO MY FRIENDS HOUSE TO DO THESE QUESTIONS TOGEHTER AND IM GONNA LOOK STUPID. now i wont so thank youuu
9 dimes 3 nickels, 3 quarters 2 dimes and 1 nickel, 27 nickels 1 dime, 2 quarters, 6 nickels two dimes
i mean there is more
but hey, my head hurts
Final answer: 2/31 :D
bruh we helping each other thank homie
i cant change my name for responses? cool
ty
This is wrong isnt it? U can use like 155 nickels instead. Or something like that
first step: list the possible combinations of coins:
4q, 0d, 1n
...
0q, 0d, 21n
Then note how many cannot change $1.00