Question

A capacitor acquires 0.002 coulomb when 50 volts is applied. Its capacitance is

a. 0.4 microfarad
b. 4.0 microfarads
c. 40.0 microfarads
d. 400.0 microfarads

Answer 1

Q = CV

Answer 2

[AI-generated answer — Clown Bot]

Well, well, well, it seems like we have a capacitor conundrum here! Let's tackle this volt-filled question with a splash of humor.

To find the capacitance, we can use the formula C = Q/V, where C is the capacitance in farads, Q is the charge in coulombs, and V is the voltage in volts. In this case, the charge acquired by the capacitor is 0.002 coulombs, and the voltage applied is 50 volts.

So, plugging in those values, we get C = 0.002 coulombs / 50 volts. Simplifying that, we find C = 0.00004 farads.

Hmmm, that answer isn't among the options. But have no fear, we just need to convert farads to microfarads. Since 1 microfarad is equal to 1 * 10^-6 farads, let's multiply our answer by 10^6 to convert it.

Calculating that, we get C = 0.00004 farads * 10^6 = 40 microfarads.

So, the capacitance of the capacitor is 40.0 microfarads, which just so happens to be option c. Voila!

Answer 3

[AI-generated answer — Step-by-Step Bot]

To find the capacitance, we can use the formula:

C = Q/V

Where:
C is the capacitance
Q is the charge acquired by the capacitor
V is the voltage applied to the capacitor

Given:
Q = 0.002 coulomb
V = 50 volts

Plugging these values into the formula:

C = 0.002 coulomb / 50 volts

C = 0.00004 farad

Since the given options are in microfarads, we need to convert the result into microfarads.

1 farad is equal to 1,000,000 microfarads.

Therefore,

C = 0.00004 farad * 1,000,000 microfarads / 1 farad

C = 40 microfarads

Therefore, the correct answer is c. 40.0 microfarads.

Answer 4

[AI-generated answer — Explain Bot]

To find the capacitance of the capacitor, we can use the formula:

C = Q / V

Where:
C is the capacitance in farads
Q is the amount of charge in coulombs
V is the voltage in volts

In this case, we are given that the capacitor acquires 0.002 coulombs of charge when 50 volts is applied. Let's substitute these values into the formula:

C = 0.002 C / 50 V

Now, we can simplify the equation:

C = 0.002 C / 50 V
C = 0.00004 F or 4.0 * 10^(-5) F

Since the units in the options are in microfarads (µF), we need to convert the capacitance from farads to microfarads by multiplying by 10^6:

C = 4.0 * 10^(-5) F * 10^6 = 40 µF

Therefore, the capacitance of the capacitor is 40.0 microfarads (c).