take a minute to notice that the point is on the axis of symmetry...
1. A following distance greater than three seconds is advised when you (1 point) are followed by a motorcycle. are driving uphill. are first learning to drive.*** are being tailgated. 2. If the vehicle following you is too close, what action can you take
given the line 5x-4y=8, find the equation of a line parallel to this line that passes through the point (3, -2) thank you
1) Use the point on the line and the slope m of the line to find three additional points through which the line passes. (There are many correct answers.) (1, 6), m is undefined the options for 2 are a) (1, -2), (-1, -2), (-2, -2) b) (1, -6), (3, -6), (5,
The slope of the line normal to the graph of 4 sin x + 9 cos y = 9 at the point (pi, 0) is: Derivative: 4cosx - 9siny(dy/dx) = 0 (dy/dx) = (-4cosx) / (-9siny) (dy/dx) = (4) / 0 Normal line = -1 / (4/0) Does this mean that the slope of the normal line is
A) The point p(3,1) lies on the curve y= square root x-2. If Q is the point (x, square root x-2) use your calculator to find the slope of the decant line PQ for the following values of x 1) 2.5 2.) 2.9 3.) 2.99 4.) 2.999 5.) 3.5 6.) 3.1 7.) 3.01 8.) 3.001
The line that is normal to the curve x^2=2xy-3y^2=0 at(1,1) intersects the curve at what other point? Please help. Thanks in advance. We have x2=2xy - 3y2 = 0 Are there supposed to be 2 equal signs in this expression or is it x2 + 2xy - 3y2 = 0 ? I'll
Find the slope of the tangent line to the curve (sqrt(4x+y))+(sqrt(3xy)) at the point (3,4) The slope of the tangent line to the curve at the given point is ? I got -((1/2)+4sqrt(36))/((1/8)+3sqrt(36))
1) The sides of the triangle shown increase in such a way that (dz/dt=1) and (dx/dt=(3dy/dx)) At the instant when x = 12 and y = 5, what is the value of dx/dt? 2) Let f(x) = x^3 − 4. Which of these is the equation for the normal line to this curve at the
Suppose that f(x) is an invertible function (that is, has an inverse function), and that the slope of the tangent line to the curve y = f(x) at the point (2, –4) is –0.2. Then: (Points : 1) A) The slope of the tangent line to the curve y = f –1(x) at
4. Given ln(x/y) + y^3 - 2x = -1. A. Find the equation of the normal line to the curve ln(x/y) + y^3 - 2x = -1 at the point (1,1). (I got -2x+3) B. Find the equation of a tangent line to the curve y=e^(x^2) that "also" passes through the point (1,0). You
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