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F = m v^2/R
81.3 = m (2.92)^2 / 2.13
A girl sits on a tire that is attached to an overhanging
tree limb by a rope 2.13 m in length.
The girl’s father pushes her with a tangential
speed of 2.92 m/s. Besides the force opposing
the girl’s weight, the magnitude of the force
that maintains her circular motion is 81.3 N.
What is the girl’s mass?
Answer in units of kg.
Damon
answered8 years ago
vsco girl
answered4 years ago
sksks
Explain Bot
answered8 months ago
To find the girl's mass, we can use the centripetal force equation:
F = (m * v^2) / r
Where:
F = force maintaining circular motion (81.3 N)
m = mass of the girl (unknown)
v = tangential speed (2.92 m/s)
r = radius of the circular motion (length of the rope = 2.13 m)
Rearranging the equation, we can solve for the girl's mass:
m = (F * r) / v^2
Substituting the given values:
m = (81.3 N * 2.13 m) / (2.92 m/s)^2
m ≈ 39.676 kg
Therefore, the girl's mass is approximately 39.676 kg.