Determine the number of moles of

a) N atoms in a sample of C7H5(NO2)3 that has the same number of O atoms as 12.6g C6H12O6

Someone posted a way to answer this question but i still don't understand

i figured i would find the number of moles of oxygen from 12.6g of C6H12O6, after that i get lost

ok the molar mass of C6H1206 IS

6(12.01)+ 12(1.008)+ 6(16.00) = 180.16

THEN FIND THE MOLE
n=m/M = 12.6/180.16 = 0.0699

so the number of 0 atoms is
6 x 0.0699 = 0.4194

I don't know what next

ok the molar mass of C6H1206 IS

6(12.01)+ 12(1.008)+ 6(16.00) = 180.16

THEN FIND THE MOLE
n=m/M = 12.6/180.16 = 0.0699

OK to here

so the number of 0 atoms is
6 x 0.0699 = 0.4194
# O atoms is 6 x 0.0699 x 6.022 x 10^23 since there are 6.022 x 10^23 atoms in a mole of atoms.
I don't know what next

u is idiot

To determine the number of moles of N atoms in a sample of C7H5(NO2)3, we need to first find the number of moles of O atoms in 12.6g of C6H12O6. Then, we can use the stoichiometry of C7H5(NO2)3 to calculate the number of moles of N atoms.

1. Calculate the number of moles of O atoms in 12.6g C6H12O6 using its molar mass. The molar mass of C6H12O6 is calculated as follows:

Molar mass of C = 12.01 g/mol
Molar mass of H = 1.008 g/mol
Molar mass of O = 16.00 g/mol

C6H12O6 has 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.

Total molar mass of C6H12O6 =
(6 * 12.01 g/mol) + (12 * 1.008 g/mol) + (6 * 16.00 g/mol)

Once you have the molar mass of C6H12O6, divide the given mass (12.6g) by its molar mass to obtain the number of moles of C6H12O6 atoms.

2. Use the stoichiometry of C7H5(NO2)3 to determine the number of moles of N atoms.

The chemical formula C7H5(NO2)3 indicates that each molecule contains 3 nitro groups (NO2). Each nitro group consists of one nitrogen atom (N) and two oxygen atoms (O).

Therefore, for every 3 nitro groups, there are 3 nitrogen atoms (N) and 6 oxygen atoms (O).

To calculate the number of moles of N atoms, we need to know the molar mass of C7H5(NO2)3 and the number of moles of O atoms we found in step 1.

Once we have the molar mass of C7H5(NO2)3, we can use the stoichiometry to find the number of moles of N atoms by setting up a ratio:

Moles of N atoms = (moles of O atoms from step 1) * (moles of N atoms per mole of C7H5(NO2)3) / (moles of O atoms per mole of C7H5(NO2)3)

Plug in the values for moles of O atoms from step 1 and the ratios obtained from the chemical formula C7H5(NO2)3 to calculate the number of moles of N atoms.

So let us see that figuring.

And you may not understand the way I do it either. Instead of us posting until you do, why don't you post how it should be worked and tell us, in detail, what you don't understand about it.