Question

Two bulbs each of resistance 2.0ohms are connected in parallelwith a battery.calculate the current flowing through any of the bulbs if the voltage of the battery is 0.2v

Answer 1

each bulb: current=voltage/resistance=.2/2=.10 ampere

Answer 2

Female

Answer 3

[AI-generated answer — Step-by-Step Bot]

To calculate the current flowing through any of the bulbs in a parallel circuit, we can use Ohm's Law, which states that the current (I) flowing through a component is equal to the voltage (V) across the component divided by the resistance (R) of the component. Mathematically, it can be represented as:

I = V / R

In this case, we have two bulbs connected in parallel, which means that the voltage (V) across each bulb will be the same, equal to the voltage of the battery (0.2V). The resistance (R) of each bulb is given as 2.0 ohms.

So, substituting the given values into the formula, we get:

I = 0.2V / 2.0 ohms

Calculating this expression, we find:

I = 0.1 A

Therefore, the current flowing through any of the bulbs is 0.1 Amperes.

Answer 4

[AI-generated answer — Explain Bot]

To calculate the current flowing through any of the bulbs, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) across the circuit divided by the resistance (R) in the circuit.

In this case, we have two bulbs connected in parallel, which means that the voltage across each bulb will be the same. Therefore, the voltage across each bulb is 0.2V.

Since the bulbs are connected in parallel, the total resistance of the circuit can be calculated using the formula: 1/RTotal = 1/R1 + 1/R2.

Given that each bulb has a resistance of 2.0 ohms, the total resistance would be:
1/RTotal = 1/2.0 + 1/2.0
= 1/2 + 1/2
= 2/2
= 1
RTotal = 1/1
= 1.0 ohm

Now we have the voltage (V) across the circuit (0.2V) and the total resistance (RTotal=1.0 ohm). We can substitute these values into Ohm's Law (I = V/R) to calculate the current (I):
I = V/RTotal
= 0.2V / 1.0 ohm
= 0.2A

Therefore, the current flowing through any of the bulbs is 0.2 Amperes (A).