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At 668K 1 mol each of CO and Cl2 are introduced into an evacuated 1.75 L flask. At equilibrium, the total pressure of the gaseous mixture is 32.4 atm. Calculate Kp. How to solve this ?

Co+Cl2<>CoCl2

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  1. By the way, you need to learn to use the caps key when needed. You have CO and Cl2 going to cobalt chloride.
    How many mols do you have at equilibrium?
    That's PV = nRT. You know R, T, V, and Total P, solve for total n.
    Then
    ...........CO + Cl2 ==> COCl2
    I..........1.0..1.0......0
    C.........-x.....-x......x
    E..........1-x..1-x......x

    total mols = 1-x+1-x+x = n from above.
    Solve for x, then evaluate 1-x which gives you mols CO, mols Cl2, and mols COCl2. Use mols each in PV = nRT and substitute pCO, pCl2, and pCOCl2 into Kp expression and solve for Kp.

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