A car travelling with constant acceleration increases its speed from 10 m/s to 50 m/s over a distance of 60 m . how long does this take?
a. 2 seconds b. 4 seconds .
Data :
Avg Velocity = 10 + 50 / 2 = 30m/s
Distance = 60 meter
time = ?
Solution :
S= V x T
making "T" subject . Then
T= S/V
T= 60/30
T = 2 seconds . This Answer is correct , but please tell me that the way I have solved this is correct or not? Thanks
vf^2=vi^2+2ad
50^2=10^2 + 2 a 60
solve for a.
then, vf=vi+at solve for time t.
Well, your solution looks great, but I must say, it seems like a car in a real hurry! It went from 10 m/s to 50 m/s in just 60 meters? That's like me going from sitting to running a marathon in one step! But hey, physics can be weird sometimes, I guess. So, yes, your solution is correct. It took the car 2 seconds to make that impressive speed increase. Good job!
Yes, your solution is correct.
To find the time taken for the car to increase its speed from 10 m/s to 50 m/s over a distance of 60 m, you used the formula:
T = S/V
where T is the time, S is the distance, and V is the average velocity.
You correctly calculated the average velocity by taking the average of the initial and final velocities:
V = (10 + 50) / 2 = 30 m/s
Then, substituting the values into the formula, you found:
T = 60 / 30 = 2 seconds
So, the car takes 2 seconds to increase its speed from 10 m/s to 50 m/s over a distance of 60 m.
Yes, your solution is correct. To find the time it takes for the car to travel the given distance, you correctly used the formula:
T = S/V
where T is the time, S is the distance, and V is the average velocity of the car.
You correctly calculated the average velocity by adding the initial velocity of 10 m/s and the final velocity of 50 m/s and dividing the sum by 2.
Average Velocity = (10 m/s + 50 m/s) / 2 = 30 m/s
Then, substituting the values into the formula, you calculated:
T = 60 m / 30 m/s = 2 seconds
So, the correct answer is indeed 2 seconds.