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Two cars are traveling along a straight road. Car A maintains a constant speed of 79 km/h and car B maintains a constant speed of 114 km/h. At t = 0, car B is 36 km behind car A.

(a) How much farther will car A travel before car B overtakes it?
? km
(b) How much ahead of A will B be 30 s after it overtakes A?

Please use kinematics equations! Thank you!!

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2 answers

  1. 25

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  2. the only equation you really need is d=vt, or t=d/v. That gives you

    114t = 79t+36
    35t=36
    t = 36/35
    That's how long it takes B to overtake A.
    In that time, A travels 79*36/35 = 81.26 km

    You can think of this another way by noting that B is traveling 35 km/hr faster than A. So, it just takes 36/35 hours to make up the 35 km.

    (b) Knowing that B travels 35 km/hr faster than A, it's easy to figure how much ahead it is after 30s = 1/120 hr

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