n: C=10n+26
------------------
27: 10(27)+36 = 270+36 = 306
and so on with the other values
------------------
27: 10(27)+36 = 270+36 = 306
and so on with the other values
If you don't mind me asking, how did you come up with the number 36 for n when 26 is for n? My results to this problem is:
C = 10n + 26
n = 27
10*27 = 270
270 + 26 = 296
(n)27/(C)296
As for the user @stupid at math, I would recommend to keep following this pattern to find the next few values to your table your creating.
Let's calculate the cost (C) for each number of people (n) attending the concert:
For n = 27:
C = 10n + 26
C = 10(27) + 26
C = 270 + 26
C = 296
For n = 39:
C = 10n + 26
C = 10(39) + 26
C = 390 + 26
C = 416
For n = 43:
C = 10n + 26
C = 10(43) + 26
C = 430 + 26
C = 456
Therefore, the table of input/output pairs is as follows:
| n | C |
|---|------|
| 27| 296 |
| 39| 416 |
| 43| 456 |
The first column represents the number of people attending the concert (n), and the second column represents the cost of the concert in dollars (C).
Let's calculate the cost for three different values of n: 27, 39, and 43.
For n = 27:
C = 10n + 26
C = 10(27) + 26
C = 270 + 26
C = 296
For n = 39:
C = 10n + 26
C = 10(39) + 26
C = 390 + 26
C = 416
For n = 43:
C = 10n + 26
C = 10(43) + 26
C = 430 + 26
C = 456
Now, we can create the table as follows:
| People (n) | Cost (C) |
|------------|----------|
| 27 | 296 |
| 39 | 416 |
| 43 | 456 |
This table represents the input/output pairs, where the number of people attending the concert (n) is the input and the corresponding cost of the concert (C) is the output.