a = F/M = 8/0.5 = 16 m/s^2
V^2 = Vo + 2a*d
Vo = 0
a = 16 m/s^2
d = 4 m.
Solve for V(m/s).
V^2 = Vo + 2a*d
Vo = 0
a = 16 m/s^2
d = 4 m.
Solve for V(m/s).
The force acting on the block is given as 8.0 N and the mass is given as 0.50 kg. We can calculate the acceleration using Newton's second law:
Force = mass x acceleration
8.0 N = 0.50 kg x acceleration
Rearranging the equation to solve for acceleration:
acceleration = Force / mass
acceleration = 8.0 N / 0.50 kg
acceleration = 16 m/s^2
Now that we have the acceleration, we can use the equations of motion to find the final velocity of the block. We can use the following equation:
v^2 = u^2 + 2as
Where:
v = final velocity
u = initial velocity (which is 0 m/s since the block starts from rest)
a = acceleration (which is 16 m/s^2 as calculated above)
s = distance (which is given as 4 m)
Plugging in the values into the equation:
v^2 = 0 + 2 x 16 m/s^2 x 4 m
v^2 = 128 m^2/s^2
Taking the square root of both sides:
v = √(128 m^2/s^2)
v ≈ 11.31 m/s
Therefore, the block's velocity after being acted upon by a force of 8.0 N for a distance of 4 m would be approximately 11.31 m/s.