Well, imagine these cards are on a blind date. The odds of a "1" card being chosen on the first try are 2 out of 6, which simplifies to 1 out of 3, or 33.33333...%.
If a "1" card is not drawn on the first try, the odds of a "1" card being chosen on the second try go down. Now, there are 5 cards remaining, but only 1 of them is a "1" card. So the odds drop to 1 out of 5, or 20%.
Finally, if a "1" card is not drawn on the second try, there are only 4 cards left, but still only 1 of them is a "1" card. So the odds decrease to 1 out of 4, or 25%.
To find the probability that a "1" card is chosen before the third card is drawn, we need to multiply the probabilities of each event happening in sequence:
1/3 × 4/5 × 1/4 = 4/60 = 1/15
So the probability is 1 out of 15, or approximately 6.666666...%.