This figure below describes the joint PDF of the random variables X and Y. These random variables take values in [0,2] and [0,1], respectively. At x=1, the value of the joint PDF is 1/2.
(figure belongs to "the science of uncertainty)
1. Are X and Y independent? NO
2. Find fX(x). Express your answers in terms of x using standard notation .
If 0<x<1,
fX(x)= x/2
If 1<x<2,
fX(x)= 3*x/2+3
Find fYX(y∣0.5).
If 0<y<1/2,
fYX(y∣0.5)= 2
3. Find fXY(x∣0.5).
If 1/2<x<1,
fXY(x∣0.5)= 0.5
If 1<x<3/2,
fXY(x∣0.5)= 1.5
Let R=XY and let A be the event {X<0.5}. Evaluate E[R∣A].
E[R∣A]= 0.0625
Answered in full...
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3 answers

Sophia is vacationing in Monte Carlo. On any given night, she takes X dollars to the casino and returns with Y dollars. The random variable Xhas the PDF shown in the figure. Conditional on X=x, the continuous random variable Y is uniformly distributed between zero and 3x.
This figure below describes the joint PDF of the random variables X and Y. These random variables take values in [0,2] and [0,1], respectively. At x=1, the value of the joint PDF is 1/2.
1. Are X and Y independent?
No
2. Find fX(x). Express your answers in terms of x, using the standard notation.
If 0<x≤1:
fX(x)= 1/2⋅x
If 1<x<2:
fX(x)= −3⋅x/2+3
If x<0 or x≥2:
fX(x)= 0
3. Find fY∣X(y∣0.5).
If 0<y<1/2:
fYX(y∣0.5)= 2
If y<0 or y>1/2:
fYX(y∣0.5)= 0
4. Find fX∣Y(x∣0.5).
If 1/2<x<1:
fXY(x∣0.5)=
If 1<x<3/2:
fXY(x∣0.5)= 1.5
If x<1/2 or x>3/2:
fXY(x∣0.5)= 0
5. Let R=XY and let A be the event that {X<0.5}. Find E[RA].
E[R∣A]= 0.0625 👍
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answered by Anonymous 
4. Find fX∣Y(x∣0.5).
If 1/2<x<1:
fXY(x∣0.5)=0.5 👍
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 ℹ️
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answered by shmalex 
4. Find fX(x).
If 1<x<2:
fX(x) = (3)*x/2+3 👍
 👎
 ℹ️
 🚩
answered by Anonymous
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