a.major league baseball player chews 17 pieces of gum per game.write anslgebraic expression to show how many pieces of gum he might chew in games
Yea, it is 17n because if he chews 2 pieces of gum every 4 days it would be 2 x 4 =8
17n
In n games, he will chew 17n sticks of gum
yeah
so is the equation n+17?
..........Ight
Thank you
a.major league baseball player chews 17 pieces of gum per game.write anslgebraic expression to show how many pieces of gum he might chew in games
The algebraic expression to show how many pieces of gum he might chew in games is:
17n
where n is the number of games he plays.
x-16=14
To solve for x, you need to isolate x on one side of the equation by performing the same operation to both sides to maintain the equality of the equation.
x - 16 = 14
Add 16 to both sides to get:
x = 14 + 16
x = 30
Therefore, the solution to the equation is x = 30.
Jamie owns 3 times as many books as Carly. Jamie owns 42 books.
If Jamie owns three times as many books as Carly, then we can solve for how many books Carly owns by dividing Jamie's number of books by 3.
Let's call the number of books Carly owns "c."
Then, we can set up an equation based on the given information:
Jamie's number of books = 3 times Carly's number of books
Or, in math terms:
42 = 3c
To solve for c, we need to isolate it on one side of the equation. To do that, we can divide both sides by 3:
42/3 = c
14 = c
So Carly owns 14 books.
-13x=-65
To solve for x, we need to isolate x on one side of the equation. We can do that by dividing both sides by -13.
-13x = -65
-divide both sides by -13-
x = -65 / -13
x = 5
Therefore, the solution for the equation is x = 5.
r/8=-6
To solve for r, we can isolate it on one side of the equation by multiplying both sides by 8.
r/8 = -6
Multiply both sides by 8:
r = -6 * 8
r = -48
Therefore, the solution for the equation is r = -48.
Gabriella owns many CDs then she gave 64 away. after donating the CDs she still had 147.
Let's call the number of CDs Gabriella initially owned "x".
After giving 64 away, she still had 147 CDs, so we can set up an equation based on the given information:
x - 64 = 147
To solve for x, we can add 64 to both sides of the equation:
x - 64 + 64 = 147 + 64
Simplifying, we get:
x = 211
Therefore, Gabriella initially owned 211 CDs.
Graph the solution of the equation. b-15=-12
To graph the solution of the equation b - 15 = -12, we can start by rearranging the equation to solve for b:
b - 15 = -12
Add 15 to both sides:
b = 3
So the solution for the equation is b = 3.
To graph this solution, we can plot the point (3, 0) on the coordinate plane, where 3 is the x-coordinate and 0 is the y-coordinate. This point represents the intersection of the line y = 0 and the vertical line passing through x = 3.
The graph is a vertical line passing through the point (3, 0) on the x-axis.
x>7
To graph the solution of the inequality x > 7, we can represent all values greater than 7.
We can plot a filled circle at the point 7 on the number line, and shade all the values greater than 7 to the right of the point:
The shaded area to the right of the filled circle represents the set of all real numbers greater than 7, which is the solution of the inequality x > 7.
x+17≤-5
To graph the solution of the inequality x + 17 ≤ -5, we can represent all values less than or equal to -22.
We can start by isolating x on one side of the inequality:
x + 17 ≤ -5
x ≤ -5 - 17
x ≤ -22
Now we can plot a filled circle at the point -22 on the number line, and shade all the values less than or equal to -22 to the left of the point:
The shaded area to the left of the filled circle represents the set of all real numbers less than or equal to -22, which is the solution of the inequality x + 17 ≤ -5.
4z>-60
To graph the solution of the inequality 4z > -60, we can divide both sides of the inequality by 4 to isolate z:
z > -60/4
z > -15
Now we can plot an open circle at the point -15 on the number line, and shade all the values greater than -15 to the right of the point:
The shaded area to the right of the open circle represents the set of all real numbers greater than -15, which is the solution of the inequality 4z > -60.
your class collected more than 250 cans of food in two weeks for the anual food drive. in the first week, 115 cans were collected. how man cans c of food were collected in the second week. Write and solve as an equality
Let c be the number of cans collected in the second week.
According to the problem, the total number of cans collected in two weeks is greater than 250:
c + 115 > 250
To solve for c, we can isolate it on one side of the inequality:
c > 250 - 115
c > 135
Therefore, the number of cans collected in the second week was greater than 135.