A circle having an area of 452 square inches is cut into two segments by a chord, which is 6 inches from the center of the circle. Find the area of the bigger segment.
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2 answers

A of smaller segment = .5r^2((theta in rad)  sin (theta in degrees))
theta = 2(arccos(6/12))
theta=120
A of larger segment = A of circle  A of smaller segment
A = 452  12^2((120pi/180)  sin120)/2
A = 363.557 👍
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the radius of the circle is 12. So, the angle θ subtended by the chord is 2π/3.
The area of the smaller segment is
1/2 r^2 (θsinθ)
That should get you started. 👍
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