how do i solve -4x-2y=-12 and 4x+8y=-24 using the elimination method?
-4x-2y = -12
4x+8y = -24
add the two equations and you have
6y = -36
y = -6
now use that to get x
wouldn't x=0?
<(-.-<) * HUG * / <('_'<) * HELP *
do what Steve said and then plug -6 into y
-4x-2(-6)=-12
4x+8(-6)=-24
-4x+12=-12 which equals 0
4x-48=-24 which equals 6
and those are your answers
To solve the given system of equations using the elimination method, follow these steps:
Step 1: Multiply one or both equations by a constant (if necessary) to make the coefficients of either x or y in both equations the same, but with opposite signs. In this case, we can multiply the first equation by -2 to make the coefficients of x the same:
-2(-4x - 2y) = -2(-12)
8x + 4y = 24
The system of equations now becomes:
8x + 4y = 24 (Equation 1)
4x + 8y = -24 (Equation 2)
Step 2: Add the corresponding sides of the equations to eliminate one variable. Since the coefficients of y are already the same, we can add the left sides and the right sides of the equations:
(Equation 1) + (Equation 2):
(8x + 4y) + (4x + 8y) = 24 + (-24)
12x + 12y = 0
Simplifying the equation:
12(x + y) = 0
Step 3: Solve the resulting equation to find the value of the remaining variable. In this case, we have:
12(x + y) = 0
x + y = 0
Step 4: Substitute the value of the eliminated variable back into one of the original equations to find the value of the other variable. Let's use Equation 1:
8x + 4y = 24
Substitute x + y with 0:
8x + 4(0) = 24
8x = 24
x = 24/8
x = 3
Step 5: Substitute the found value of one variable back into the equation x + y = 0 to find the value of the other variable:
3 + y = 0
y = -3
Therefore, the solution to the given system of equations is x = 3 and y = -3.