Complete the following reactions by moving only one proton at a time. Identify the acid
(A) and the base (B) on the left-hand side of the equation, and the conjugate acid (CA)
and the conjugate base (CB) on the right-hand side of the equation, according to
Bronsted-Lowry theory. The first one has been done for you as an example.
Example: HCO3
- (aq) + H2S (aq) ↔ H2CO3 (aq) + HS- (aq)
B A CA CB
a.) HNO2 (aq) + H2O (l) ↔
b.) CO3
2- (aq) + HBr (aq) ↔
c.) H2C6H5O7
- (aq) + H2SO4 (aq) ↔
And your problem is??
For a).
HNO2(aq) + H2O(l) ↔ H3O^+(aq) + NO2^-(aq)
Now you look at thwich has more H and which has fewer.
HNO2 is the acid
NO2^- on the right is the conjugate base.
H2O on the left is the base.
H3O^+ on the right is the conjugate acid.
a.) HNO2 (aq) + H2O (l) ↔ H3O+ (aq) + NO2- (aq)
B A CA CB
HNO2 H2O H3O+ NO2-
b.) CO3
2- (aq) + HBr (aq) ↔ HCO3- (aq) + Br- (aq)
B A CA CB
CO3
2- HBr HCO3- Br-
c.) H2C6H5O7
- (aq) + H2SO4 (aq) ↔ H3O+ (aq) + HC6H5O7
2- (aq)
B A CA CB
H2C6H5O7 H2SO4 H3O+ HC6H5O7
2-
To determine the acid (A), base (B), conjugate acid (CA), and conjugate base (CB) according to the Bronsted-Lowry theory, we need to understand the concept of proton transfer.
In a reaction, an acid donates a proton (H+) to a base, forming a conjugate base. Conversely, a base accepts a proton, forming a conjugate acid. The acid and base on the left-hand side of the equation are referred to as A and B, respectively. On the right-hand side, the conjugate acid and conjugate base are denoted as CA and CB, respectively.
Now, let's solve each reaction by moving one proton at a time:
a.) HNO2 (aq) + H2O (l) ↔
In this reaction, HNO2 is the acid (A) since it donates a proton, and H2O is the base (B) as it accepts the proton. The incomplete reaction can be written as:
HNO2 (aq) + H2O (l) ↔ H3O+ (aq) + NO2- (aq)
B A CA CB
b.) CO3 2- (aq) + HBr (aq) ↔
In this reaction, CO3 2- is the base (B) as it accepts a proton, and HBr is the acid (A) since it donates a proton. The incomplete reaction can be written as:
CO3 2- (aq) + HBr (aq) ↔ HCO3- (aq) + Br- (aq)
B A CA CB
c.) H2C6H5O7 - (aq) + H2SO4 (aq) ↔
In this reaction, H2C6H5O7 - is the base (B) as it accepts a proton, and H2SO4 is the acid (A) since it donates a proton. The incomplete reaction can be written as:
H2C6H5O7 - (aq) + H2SO4 (aq) ↔ H3C6H5O7 (aq) + HSO4- (aq)
B A CA CB
By following the proton transfer, we can identify the acids (A) and bases (B) on the left-hand side and the conjugate acids (CA) and conjugate bases (CB) on the right-hand side of each equation based on the Bronsted-Lowry theory.