The average weight of 3 boys is 53 pounds. Not one of these boys weighs less than 51 pounds. What is the maximum possible weight in pounds, of any one boy?
ANY ONE FROM SZABIST UNIVERSITY (HYD)
51+51+x/3=53
51+51+x=159
102+x=159
X= 159-102
X= 57
Answer
Why take Two times is 51? you can take 52 or other...can you explain this please?
Tfd
x+y+z = 53*3 = 159
if y+z = 51*2 = 102 (min x and y possible to get max x)
then x = 159 - 102 = 57
You wrote 3*159-2*51=159-102=57
So my question is that why are you putting 159 . This is even not in the question
To find the maximum possible weight of any one boy, we need to consider that the average weight of the boys is 53 pounds and not one of them weighs less than 51 pounds.
Let's assume the weights of the three boys are A, B, and C. Since not one of them weighs less than 51 pounds, the minimum weight for each boy is 51 pounds.
Since the average weight of the boys is 53 pounds, the sum of their weights is 3 x 53 = 159 pounds.
Now, if we want to find the maximum possible weight of one boy, we need to distribute the remaining weight after allowing each boy to weigh a minimum of 51 pounds.
The minimum weight for each boy is 51 pounds, so the combined minimum weight for the three boys is 3 x 51 = 153 pounds.
To find the maximum possible weight, we subtract the combined minimum weight from the sum of their weights: 159 - 153 = 6 pounds.
Therefore, the maximum possible weight, in pounds, of any one boy is 6 pounds.
If two weigh 51, that's the minimum for two boys, leaving the maximum for the 3rd boy of
3*159-2*51 = 159-102 = 57