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The potassium salt of benzoic acid, potassium benzoate, KC7H5O2, can be made by the action of potassium permanganate on toluene, C7H8.

C7H8 + 2 KMnO4 --> 2MnO2 + KOH + H2O

If the yield of potassium benzoate cannot be realistically be expected to be more than 71%, what is the minimum number of grams of toluene needed to achieve this yield while producing 11.5 g of potassium benzoate?

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3 answers
  1. Nevermind I got the answer myself!

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  2. You had a problem almost like this that Bob Pursley helped you with.
    You ant 11.5 g pot benzoate so the reaction must produce a theoretical yield of 11.5g/0.71 = ?
    Then mols K benzoate = ?/molar mass K benzoate
    Convert to mols tolune, then
    g tolune = mols x molar mass toluene.

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  3. C7H8 + 2KMnO4 ---------- KC7H5O2 + 2MnO2 + KOH + H2O

    If the yield of potassium benzoate cannot realistically be expected to be more than 71%, what is the minimum number of grams of toluene needed to produce 11.5 g of potassium benzoate?

    Group of answer choices

    9.2 g

    16 g

    8.02 g

    22.6 g

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