V = Vo + g*t = 0 + 10*1=10 m/s. T = 1s.
d = Vo*t + 0.5g*t^2
d = 10*1 + 5*1^2 = 15 m.
A. 15 meters
B. 10 meters
C. 5 meters
D. 20 meters
the way the question is worded it seems it should be 10meteres but I think it wants total so would it be A. 15 meters?
d = Vo*t + 0.5g*t^2
d = 10*1 + 5*1^2 = 15 m.
During the first second, the ball falls 5 meters. This means that the ball accelerated from rest to a speed of 9.8 m/s in one second.
In the second second, the ball continues to fall with the same acceleration. To find the distance it will fall in the second second, we need to calculate the average speed of the ball during that time.
Since the acceleration is constant, the average speed during the second second can be found by taking the average of the initial speed at the beginning of the second and the final speed at the end of the second.
The initial speed at the beginning of the second is 9.8 m/s (the speed the ball reached at the end of the first second). The final speed at the end of the second will be double the initial speed, as the acceleration continues to act on the ball.
Using these values, the average speed during the second second is (9.8 m/s + 19.6 m/s)/2 = 14.7 m/s.
To find the distance the ball will fall during the second second, we can multiply the average speed by the time, which is 1 second.
Distance = Average speed Ă— Time
Distance = 14.7 m/s Ă— 1 second = 14.7 meters
Therefore, the ball will fall approximately 14.7 meters during the second second. None of the answer choices provided match this calculation, so it appears that none of the options are correct.