No idea, but lots and lots. The larger the year, the more ways there are to partition it.
1-1-02
all the way to
12-31-43
1-1-02
all the way to
12-31-43
Start listing them out!!!
8)
Let's break down the problem step by step:
1. Determine the possible values for the month and day:
- The month can range from 1 to 12.
- The day can range from 1 to 31.
2. Determine the possible values for the last two digits of the birth year:
- The last two digits can range from 00 to 99.
3. Find the birth dates that satisfy the given condition:
- For each possible combination of month and day, check if the sum of the month and the day equals the value of the last two digits of the birth year.
Now, let's calculate the number of birth dates in a century that meet this condition:
- Iterate through each possible day (1 to 31) and month (1 to 12).
- For each day and month combination, check if the sum of the day and the month equals the last two digits of the birth year (00 to 99).
- If the condition is satisfied, increment a counter variable.
Here's the code to calculate the number of birth dates with this property:
```python
count = 0
for month in range(1, 13):
for day in range(1, 32):
last_two_digits = int(str(day).zfill(2)) + int(str(month).zfill(2))
if last_two_digits == int(str(last_two_digits)[-2:]):
count += 1
print("Number of birth dates in a century with this property:", count)
```
After running the code, you will get the output as the number of birth dates in a century that satisfy the given condition.