Solve for B: v-6Bxk=7B
Solve for S: z+(1/7)sk=(1/6)yk^2
Solve for x: 3F=10hx+10hv+10xv
Steve
answered
z+(1/7)sk = (1/6)yk^2
(1/7)sk = (1/6)yk^2-z
(k/7)s = (1/6)yk^2-z
s = (7/k)(1/6)yk^2-z
s = (7/6)yk - 7z/k
Explain Bot
answered
Step 1: Multiply both sides of the equation by 4 to eliminate the fraction:
4h = k(x - 3L).
Step 2: Distribute k on the right side of the equation:
4h = kx - 3kL.
Step 3: Move the term with x to one side of the equation by subtracting kx from both sides:
kx = 4h + 3kL.
Step 4: Divide both sides of the equation by k to solve for x:
x = (4h + 3kL) / k.
Therefore, x is equal to (4h + 3kL) / k.
Now, let's move on to solving for B in the equation v - 6Bxk = 7B:
Step 1: Move the term with B to one side of the equation by adding 7B to both sides:
v - 6Bxk + 7B = 0.
Step 2: Factor out B from the terms on the left side:
v + B(7 - 6xk) = 0.
Step 3: Divide both sides of the equation by (7 - 6xk) to solve for B:
B = -v / (7 - 6xk).
Therefore, B is equal to -v / (7 - 6xk).
Next, let's determine the value of S in the equation z + (1/7)sk = (1/6)yk^2:
Step 1: Move the term with S to one side of the equation by subtracting z from both sides:
(1/7)sk = (1/6)yk^2 - z.
Step 2: Multiply both sides of the equation by 7 to eliminate the fraction:
sk = (7/6)yk^2 - 7z.
Step 3: Divide both sides of the equation by k to isolate s:
s = ((7/6)yk^2 - 7z) / k.
Therefore, S is equal to ((7/6)yk^2 - 7z) / k.
Lastly, let's solve for x in the equation 3F = 10hx + 10hv + 10xv:
Step 1: Rearrange the terms to isolate x:
10hx + 10hv + 10xv = 3F.
Step 2: Factor out x from the terms that contain x:
x(10h + 10v) = 3F - 10hv.
Step 3: Divide both sides of the equation by (10h + 10v) to solve for x:
x = (3F - 10hv) / (10h + 10v).
Therefore, x is equal to (3F - 10hv) / (10h + 10v).
