use a table and play money to solve the problems. item prices: postcard($1.13), keychain($3.87), park ranger patch($5.33) and stuffed animal($8.79).

Jamie spent $5.00 on postcard and key chain, Darla sepent $9.20 on park ranger patch and key chain and Abraham had $5.10.

Who (janie, darla or abraham) could have paid for his or her purchases with 3 bills and 20 coins. how many dollar bills do the coins equal?

bobpursley bobpursley answered
11 years ago

You are supposed to do this with play money.

Jamie could have spend 5 dollars with 3 one dollar bills, and 20 dimes. Check that

Anonymous Anonymous answered
11 years ago

blah you cant its just hard u know

Anonymous Anonymous answered
11 years ago

98

Buns n the packet.

Note to friends: don't copy yo

Explain Bot Explain Bot answered
7 months ago

To solve this problem using a table and play money, we can create a table with the given item prices - postcard ($1.13), keychain ($3.87), park ranger patch ($5.33), and stuffed animal ($8.79).

1) First, let's find out the possible combinations of items each person could have bought with the given amounts:

- Jamie spent $5.00, so he could have bought a postcard ($1.13) and a keychain ($3.87).

- Darla spent $9.20, so she could have bought a park ranger patch ($5.33) and a keychain ($3.87).

- Abraham had $5.10, which doesn't match the exact amount of any single item. So, we need to find if Abraham could buy a combination of items totaling $5.10.

2) To determine Abraham's possible combination, we will use the table and play money to form different combinations:

- Starting with the most expensive item, the stuffed animal ($8.79), we can see it's not possible to buy this item alone since Abraham only had $5.10.

- Next, we look at the park ranger patch. Since this item costs $5.33, Abraham cannot buy it alone either.

- Now, let's try a combination of the keychain and the postcard, which is $1.13 (postcard) + $3.87 (keychain) = $5.00. Abraham had $5.10, which means he could have bought the keychain and the postcard.

3) Lastly, we need to determine the number of dollar bills that the coins equal. Since Abraham spent $5.10, which is effectively $5 + $0.10, we know that he used 5 dollar bills. The remaining 10 cents is equivalent to 10 coins (assuming they are pennies).

So, in conclusion, Abraham could have paid for his purchases ($5.10) with 3 bills (5 dollar bills) and 20 coins (10 pennies).

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