A stone is thrown straight down from the edge of a roof, 750 feet above the ground, at a speed of 7 feet per second.

A. Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 5 seconds later?

B. At what time does the stone hit the ground?

C. What is the velocity of the stone when it hits the ground?

Explain Bot Explain Bot answered
8 months ago

To find the height of the stone at 5 seconds later, we need to use the formula for displacement under constant acceleration:

Displacement = Initial Velocity * Time + 0.5 * Acceleration * Time^2

A. For the first question, we are given that the stone is thrown downward, so the initial velocity is -7 feet per second (negative because it is in the opposite direction to the positive direction of measurement). The acceleration due to gravity is -32 feet per second squared. Plugging in the values into the formula:

Displacement = -7 * 5 + 0.5 * (-32) * (5^2)
Displacement = -35 + 0.5 * (-32) * 25
Displacement = -35 - 16 * 25
Displacement = -35 - 400
Displacement = -435

Since the stone is thrown downward, the displacement is negative. Therefore, the height of the stone 5 seconds later is 435 feet below the initial height of 750 feet. We subtract 435 feet from 750 feet to get the final height:

Final Height = 750 - 435
Final Height = 315 feet

B. To find the time it takes for the stone to hit the ground, we need to set the displacement equal to zero and solve for time:

Displacement = -7 * t + 0.5 * (-32) * t^2 = 0

Simplifying the equation:
-7t - 16t^2 = 0

We can factor out a t:
t(-7 - 16t) = 0

This equation will be zero when either t = 0 or -7 - 16t = 0. Since time cannot be negative, we can solve the second equation for t:

-7 = 16t
t = -7/16

Since time cannot be negative, we discard this solution. Therefore, the only solution is t = 0. This means that the stone hits the ground at time t = 0, or immediateaneously.

C. Finally, to calculate the velocity of the stone when it hits the ground, we can use the formula:

Final Velocity = Initial Velocity + (Acceleration * Time)

Plugging in the values:
Final Velocity = -7 + (-32 * 0)
Final Velocity = -7

The negative sign indicates that the velocity is in the opposite direction of the initial velocity. Therefore, the velocity of the stone when it hits the ground is 7 feet per second, but in the opposite direction in which it was thrown.

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