2449*17=(2449+massrain)10
solve for mass of rain.
solve for mass of rain.
The initial momentum of the system, consisting of the railroad car and the rainwater, is given by the mass of the car multiplied by its initial velocity:
Initial momentum = (mass of car) ร (initial velocity of car)
The final momentum of the system is given by the mass of the car, including the accumulated water, multiplied by its final velocity:
Final momentum = (mass of car + mass of water) ร (final velocity of car)
According to the principle of conservation of momentum, the initial momentum of the system is equal to the final momentum of the system. Therefore, we can set up the equation:
(mass of car) ร (initial velocity of car) = (mass of car + mass of water) ร (final velocity of car)
Substituting the given values into the equation, we have:
2449 kg ร 17 m/s = (2449 kg + mass of water) ร 10 m/s
To solve for the mass of water, we can rearrange the equation:
mass of water = (2449 kg ร 17 m/s - 2449 kg ร 10 m/s) / 10 m/s
mass of water = (2449 kg ร (17 m/s - 10 m/s)) / 10 m/s
mass of water = (2449 kg ร 7 m/s) / 10 m/s
mass of water = 17143 kgยทm/s / 10 m/s
mass of water = 1714.3 kg
Therefore, approximately 1714.3 kilograms of water has accumulated in the car.