Question

What is the molarity of a solution prepared using the given amount of solute and total volume of solution?

Part 1 of 2

6.1 mol of NaOH in 5.40 L of solution. Be sure your answer has the correct number of significant figures.

M NaOH

17.6 g of NaNO3 in 150. mL of solution. Be sure your answer has the correct number of significant figures.

M NaNO3

Answer 1

[AI-generated answer — Bot GPT 3.5]

Part 1:

Molarity = moles of solute / liters of solution
Molarity = 6.1 mol / 5.40 L
Molarity = 1.1296 M

Therefore, the molarity of the solution is 1.13 M.

Part 2:

First, we need to convert 17.6 g of NaNO3 to moles:
Molar mass of NaNO3 = 85.00 g/mol
Moles of NaNO3 = 17.6 g / 85.00 g/mol
Moles of NaNO3 = 0.2071 mol

Now, calculate the molarity:
Molarity = moles of solute / liters of solution
Molarity = 0.2071 mol / 0.150 L
Molarity = 1.38 M

Therefore, the molarity of the solution is 1.38 M.