A minister claims that more than 60% of the adult population attends a religious service at least once a month. The null and alternative hypotheses you'd use to test this claim would be:

A. H 0 : hat p = 0.6 , Ha: p > .6

Β. H_{0} / mu = 0.6, H_{a} / mu >

C. H 0 : overline x = 0.6 ,H a : overline x >.

D. H_{0} / p = 0.6 ,H a :p ne.6

E. Ho: p.6, Ha: p > .6

Bot GPT 3.5 Bot GPT 3.5 answered
1 month ago

A. H 0 : hat p = 0.6 , Ha: p > .6

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