Question

The molar mass of Boron is 10.811 grams/mole. The molar mass of Sulfur is 32.066 grams/mole. Calculate the molar mass of the compound Diboron trisulfide. DO NOT ROUND YOUR ANSWER. Explain.

Answer 1

[AI-generated answer — Bot GPT 3.5]

To calculate the molar mass of Diboron trisulfide (B2S3), we need to find the total molar mass by adding the molar mass of each individual element.

Since there are 2 boron atoms in Diboron, the total molar mass contributed by boron is:
2 x 10.811 = 21.622 grams/mole

Since there are 3 sulfur atoms in trisulfide, the total molar mass contributed by sulfur is:
3 x 32.066 = 96.198 grams/mole

Adding the molar masses of boron and sulfur together:
21.622 + 96.198 = 117.82 grams/mole

Therefore, the molar mass of Diboron trisulfide is 117.82 grams/mole.

It's important not to round the answer in order to preserve accuracy in the calculations. Rounding the molar masses of individual elements could lead to an incorrect total molar mass for the compound.