Question

For the direct variation equation y=38x

, what is the constant of proportionality?(1 point)
The constant of proportionality is

Answer 1

[AI-generated answer — Bot GPT 3.5]

38

Answer 2

[AI-generated answer — Step-by-Step Bot]

the coefficient of x in the equation, which is 38 in this case.

Answer 3

[AI-generated answer — Explain Bot]

the coefficient of x in the equation, which in this case is 38.

To find the constant of proportionality in a direct variation equation, you need to compare the ratio of y to x in the equation. In this case, the equation y = 38x tells us that y is directly proportional to x, with a constant of proportionality of 38.

Answer 4

Donte is told that for a particular math problem, the value of y

is always 8 times the value of x
. Donte writes the equation y=8x
to show the relationship between x
and y
. What is the constant of proportionality?(1 point)
The constant of proportionality is

Answer 5

[AI-generated answer — Bot GPT 3.5]

8

Answer 6

A hummingbird flaps its wings 5,000 times a minute when hovering in place. How many times will it flap its wing in 15 seconds?(1 point)

Answer 7

[AI-generated answer — Bot GPT 3.5]

To find out how many times the hummingbird will flap its wings in 15 seconds, we first need to convert the rate from minutes to seconds.

The hummingbird flaps its wings 5,000 times a minute. Since there are 60 seconds in a minute, we have:

5000 flaps/minute * 1 minute/60 seconds = 83.33 flaps/second (approximately)

Therefore, the hummingbird will flap its wings approximately 83.33 times in 1 second.

To find out how many times it will flap its wings in 15 seconds, we multiply the rate by the time:

83.33 flaps/second * 15 seconds = 1249.95 flaps (approximately)

Therefore, the hummingbird will flap its wings approximately 1249.95 times in 15 seconds.

Answer 8

A hummingbird flaps its wings 5,000 times a minute when hovering in place. How many times will it flap its wing in 15 seconds?(1 point)

The hummingbird will flap its wings
times.

Answer 9

[AI-generated answer — Bot GPT 3.5]

To find out how many times the hummingbird will flap its wings in 15 seconds, we need to determine the proportion between the number of flaps per minute and the number of flaps per second.

We know that the hummingbird flaps its wings 5,000 times a minute.

To convert this rate to flaps per second, we need to divide by the number of seconds in a minute:

5,000 flaps/minute ÷ 60 seconds/minute = 83.33 flaps/second (approximately)

Therefore, the hummingbird flaps its wings approximately 83.33 times in 1 second.

To find out how many times it will flap its wings in 15 seconds, we multiply the rate by the time:

83.33 flaps/second * 15 seconds = 1250 flaps (approximately)

Therefore, the hummingbird will flap its wings approximately 1250 times in 15 seconds.

Answer 10

In 2 days, Quinesha exercises 50 minutes. At this rate, how many minutes does she exercise in 4 weeks?(1 point)

Quinesha exercises
minutes in 4 weeks.

Answer 11

[AI-generated answer — Bot GPT 3.5]

To find out how many minutes Quinesha exercises in 4 weeks, we first need to determine the proportion between the number of minutes she exercises in 2 days and the number of minutes in 4 weeks.

We know that Quinesha exercises 50 minutes in 2 days.

To convert this rate to minutes in 1 day, we divide by the number of days in 2 days:

50 minutes/2 days = 25 minutes/day

Therefore, Quinesha exercises 25 minutes per day.

To find out how many minutes she exercises in 4 weeks, we multiply the rate by the number of days in 4 weeks:

25 minutes/day * 7 days/week * 4 weeks = 700 minutes

Therefore, Quinesha exercises 700 minutes in 4 weeks.