Combining like terms, we can simplify the expression to:
(9x - 5x) + (3y + 4y) + (-6 - 3)
4x + 7y - 9
(9x - 5x) + (3y + 4y) + (-6 - 3)
4x + 7y - 9
(9 - 4) / 11z
5/11z
(3/10x + 3/10x) + (1/6y + 3/6y)
6/10x + 4/6y
Next, we can simplify the fractions, if possible. First, we can simplify 6/10x by dividing the numerator and denominator by 2:
3/5x + 4/6y
Now, we need to find a common denominator for the fractions. The least common multiple of 5 and 6 is 30, so we can write each fraction with a denominator of 30:
(3/5)(6/6)x + (4/6)(5/5)y
18/30x + 20/30y
Finally, we can simplify the expression further:
(18x + 20y) / 30
Thus, the simplified expression is 18x + 20y / 30.
(3/10x + 3/10x) + (1/6y + 3/6y)
6/10x + 4/6y
Next, we can simplify the fractions. Simplifying 6/10 and 4/6, we get:
3/5x + 2/3y
Therefore, the simplified expression is 3/5x + 2/3y.
A. 12x^2
B. 4+8x
C. 12x
D. 4x+8
4x + 8x = 12x
Therefore, the simplified expression is 12x.
A. 2gh - 4gh
B. 3g -5h
C. -2gh
D. 3g + 5g
Question 3: Simplify 2a − 4b +7 + 8a + 6b − 2.
A. 12ab + 5
B.2ab + 14ab + 5
C.10a − 2b +5
D. 10a + 2b +5
Question 4: Simplify 3/7x + 2/7x using properties of operations.
A. 5/7x2
B. 5/14x2
C. 5/7x
D. 5/14x
Question 5: Simplify 6/7c − 5/9d − 1/2 c + 1/3d
A. 5/14c - 2/9d
B. 5/9c - 4/12d = 5/9c - 1/3d
C. 5/14c + 2/9d
D. 5/9c + 4/12d = 5/9c + 1/3d
To simplify this expression, we can combine like terms by adding the coefficients of the variables:
9g - 6g + (-7h) + 2h
= (9g - 6g) + (-7h + 2h)
= 3g - 5h
The simplified expression is 3g - 5h.
Therefore, the answer is B. 3g - 5h.
Question 3: Simplify 2a − 4b +7 + 8a + 6b − 2.
To simplify this expression, we can combine like terms by adding the coefficients of the variables:
(2a + 8a) + (-4b + 6b) + (7 - 2)
= 10a + 2b + 5
The simplified expression is 10a + 2b + 5.
Therefore, the answer is D. 10a + 2b + 5.
Question 4: Simplify 3/7x + 2/7x using properties of operations.
To simplify this expression, we can combine the fractions because they have the same denominator:
(3/7 + 2/7)x
= 5/7x
The simplified expression is 5/7x.
Therefore, the answer is C. 5/7x.
Question 5: Simplify 6/7c − 5/9d − 1/2 c + 1/3d.
To simplify this expression, we can combine the terms with the same variables:
(6/7c - 1/2c) + (-5/9d + 1/3d)
= (12/14c - 7/14c) + (-15/27d + 9/27d)
= 5/14c - 6/27d
The simplified expression is 5/14c - 6/27d.
Therefore, the answer is A. 5/14c - 2/9d.
A. Kinetic and potential energy are increasing.
B. Potential energy is increasing, and kinetic energy is decreasing.
C.Kinetic energy is increasing, and potential energy is decreasing.
D.Kinetic and potential energy are decreasing.
C. Kinetic energy is increasing, and potential energy is decreasing.
As she starts to come down, her potential energy decreases because she is closer to the ground. At the same time, her kinetic energy increases as she gains speed and movement.
A. in the middle of the ramp at its lowest point in the U
B. at the top of the ramp before they begin moving down into the ramp
C. on the other side of the ramp as the person is coming back up
D. on the first part of the ramp as the person is moving down the side
B. at the top of the ramp before they begin moving down into the ramp.
At the highest point of the U-shaped ramp, the person has the greatest potential energy because they are at the highest elevation. Potential energy is directly related to height, so as the person is higher up on the ramp, their potential energy increases.
A.The potential energy is increasing at point A because the bicyclist is moving fastest at that point.
B. The potential energy is always decreasing because the bicyclist continues to move forward.
C. The potential energy is increasing at point B because the bicyclist is highest there.
D. The potential energy is increasing at point C because the bicyclist is increasing in elevation at that point.
D. The potential energy is increasing at point C because the bicyclist is increasing in elevation at that point.
Potential energy is directly related to height. At point C, the bicyclist is increasing in elevation, which means their potential energy is also increasing. As they ride from right to left, they reach a higher point at point C, resulting in an increase in potential energy.
A. half way down
B. at the bottom
C. quarter of the way down
D. at the top
B. at the bottom.
When the banana is at the bottom of the cliff, its potential energy is zero because it is at the lowest point and has no height from which to fall. At the same time, its kinetic energy is at its maximum because it is moving at its fastest speed right before impact. Therefore, at the bottom of the cliff, the potential and kinetic energies of the banana are equal.