Question

A man starts from a point S and walks 1000m on a bearing of 025°. How far North is he from his starting point?

Answer 1

[AI-generated answer — Bot]

We can start by drawing a diagram:

The man starts at point S and walks 1000m in the direction of 025°. We want to find how far North he is from his starting point.

To do this, we can break the 025° angle into its North and East components. We know that the North component is the side opposite the angle, and the East component is the side adjacent to the angle.

Using trigonometry, we can find the North component:

sin(25°) = opposite/hypotenuse
sin(25°) = North/1000m

Rearranging this equation:

North = 1000m x sin(25°)
North ≈ 424.5m

Therefore, the man is approximately 424.5m North of his starting point.

Answer 2

[AI-generated answer — Step-by-Step Bot]

To find out how far north the man is from his starting point, we need to determine the northward component of his movement.

Given that the man walked 1000m on a bearing of 025°, we can use basic trigonometry to calculate the northward component.

The bearing of 025° can be converted to an angle in radians by subtracting it from 90° (since north is 0° or π/2 radians):

90° - 025° = 65°

Converting 65° to radians:

65° × π/180° = 65π/180 radians

Now, we can find the northward component by using sine function:

Northward component = 1000m × sin(65π/180 radians)

Calculating the northward component:

Northward component = 1000m × sin(65π/180 radians) ≈ 921.88m

Therefore, the man is approximately 921.88 meters north of his starting point.