Question

what mass of sodium carbonate is to 500cm³ of 0.1 molar sodium carbonate solution ( given na=23, c= 12, o=16)

Answer 1

[AI-generated answer — Explain Bot]

To find the mass of sodium carbonate required, we can use the formula:

Mass = Molarity × Volume × Molar Mass

Step 1: Calculate the molar mass of sodium carbonate (Na2CO3).

2 × Na = 2 × 23 = 46 g/mol
1 × C = 1 × 12 = 12 g/mol
3 × O = 3 × 16 = 48 g/mol

Molar mass of Na2CO3 = 46 + 12 + 48 = 106 g/mol

Step 2: Calculate the number of moles of sodium carbonate using the molarity and volume of the solution.

Molarity = Number of moles / Volume

Number of moles = Molarity × Volume

Given:
Molarity = 0.1 mol/dm³ (or 0.1 M)
Volume = 500 cm³ (or 0.5 dm³)

Number of moles = 0.1 × 0.5 = 0.05 moles

Step 3: Calculate the mass of sodium carbonate using the number of moles and molar mass.

Mass = Number of moles × Molar mass

Mass = 0.05 moles × 106 g/mol = 5.3 grams

Therefore, the mass of sodium carbonate required is 5.3 grams.