Question

if a man pulls a rope with a constant force of 20.0N, what is the acceleration of the system (crate plus dolly) and how far will it move in 2.00s? Assume the system sarts from rest and that there are no friction forces opposing the motion.

Answer 1

need mass

F = ma
s = 1/2 at^2

Answer 2

[AI-generated answer — Explain Bot]

To find the acceleration of the system, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration: F = ma.

In this case, the only force acting on the system is the force applied by the man pulling the rope with a constant force of 20.0 N. Therefore, the net force is equal to 20.0 N. The mass of the system (crate plus dolly) is not provided, so let's assume it to be "m."

Using Newton's second law, we can write the equation as follows:

20.0 N = m * a

Next, we need to find the acceleration of the system. Since the force is constant and the system starts from rest, we can rearrange the equation to solve for acceleration:

a = (20.0 N) / m

Now, let's calculate the distance traveled by the system in 2.00 seconds. To do this, we can use the kinematic equation:

d = v₀t + (1/2)at²

Here, v₀ represents the initial velocity (which is zero since the system starts from rest), t is the time (2.00 seconds), a is the acceleration we calculated, and d is the distance traveled.

Since the initial velocity is zero, the equation simplifies to:

d = (1/2)at²

Now, we can plug in the values we have to calculate the distance traveled:

d = (1/2) * (20.0 N / m) * (2.00 s)²

Simplifying further:

d = (10.0 N/m) * 4.00 s²

d = 40.0 Ns²/m

Therefore, the acceleration of the system is 20.0 N/m, and it will move a distance of 40.0 Ns²/m in 2.00 seconds.

Answer 3

[AI-generated answer — Step-by-Step Bot]

To find the acceleration of the system, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The formula is:

a = F_net / m

Given:
Force (F_net) = 20.0 N
Mass (m) = mass of the crate + mass of the dolly (which is not provided)

Since the mass of the system is not provided, we cannot calculate the exact acceleration without it. However, we can still answer the second part of your question, which is calculating how far it will move in 2.00 seconds.

To find the distance covered, we can use the kinematic equation:

d = v_i * t + 0.5 * a * t^2

Given:
Initial velocity (v_i) = 0 (since the system starts from rest)
Time (t) = 2.00 seconds

Now, let's calculate the distance covered:

d = 0 * 2.00 + 0.5 * a * (2.00)^2
d = 0 + a * 0.5 * 4
d = 2 * a

Therefore, the distance covered by the system in 2.00 seconds is 2 times the acceleration. However, to calculate the exact value, we need to know the mass of the system.