3^2 + h^2 = 11^2
h^2 = 112
h = √112 = ...
h^2 = 112
h = √112 = ...
√ (11² - 3²) = √ (121 - 9) = √ 112 = 10.583 ft
In this case, the ladder is the hypotenuse, the distance from the base of the ladder to the building is one side, and the height the ladder will reach against the building is the other side.
Let's use variables to represent the values. Let's call the height the ladder will reach "h", and the distance from the base of the ladder to the building "d".
According to the information given:
- The base of the ladder is 3ft away from the building, so d = 3ft.
- The length of the ladder is given as 11ft.
Using the Pythagorean theorem:
h^2 = (d^2) + (ladder length^2)
h^2 = (3ft^2) + (11ft^2)
h^2 = 9ft^2 + 121ft^2
h^2 = 130ft^2
To solve for h, we need to square root both sides of the equation:
h = √(130ft^2)
h ≈ 11.40ft
Therefore, the ladder will reach approximately 11.40 feet against the building.