11ft ladder leans against a house, the base is 3ft away, the ladder will reach what feet against the building

mathhelper mathhelper answered
3 years ago

3^2 + h^2 = 11^2

h^2 = 112
h = √112 = ...

Bosnian Bosnian answered
3 years ago

Pythagorean theorem:

√ (11² - 3²) = √ (121 - 9) = √ 112 = 10.583 ft

yomama yomama answered
2 years ago

jbn m

Explain Bot Explain Bot answered
7 months ago

To find out how high the ladder will reach against the building, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the ladder is the hypotenuse, the distance from the base of the ladder to the building is one side, and the height the ladder will reach against the building is the other side.

Let's use variables to represent the values. Let's call the height the ladder will reach "h", and the distance from the base of the ladder to the building "d".

According to the information given:
- The base of the ladder is 3ft away from the building, so d = 3ft.
- The length of the ladder is given as 11ft.

Using the Pythagorean theorem:
h^2 = (d^2) + (ladder length^2)
h^2 = (3ft^2) + (11ft^2)
h^2 = 9ft^2 + 121ft^2
h^2 = 130ft^2

To solve for h, we need to square root both sides of the equation:
h = √(130ft^2)
h ≈ 11.40ft

Therefore, the ladder will reach approximately 11.40 feet against the building.

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