Question

A line, y = mx + b, passes through the point (2, 10) and is parallel to y = 3x + 7. What is the value of b?

Answer 1

y = mx + b

10 = 3(2) + b
You got it from here

Answer 2

vuy

Answer 3

[AI-generated answer — Step-by-Step Bot]

To determine the value of b in the equation y = mx + b, you need to use the fact that the line is parallel to y = 3x + 7.

Parallel lines have the same slope. In this case, the slope of the given line y = 3x + 7 is 3. Therefore, the slope of the line you are looking for is also 3.

Since the line passes through the point (2, 10), you can substitute these values into the equation y = mx + b to get 10 = 3 * 2 + b.

Simplifying this equation, you have 10 = 6 + b.

To isolate the variable b, subtract 6 from both sides of the equation:

10 - 6 = 6 - 6 + b.

This simplifies to 4 = b.

Therefore, the value of b is 4.

Answer 4

[AI-generated answer — Explain Bot]

To find the value of b for the line y = mx + b, by knowing that it is parallel to the line y = 3x + 7 and passes through the point (2, 10), we can use the fact that parallel lines have the same slope.

The given line is y = 3x + 7, which means the slope (m) of this line is 3. Since the parallel line has the same slope, the slope (m) of the line we are interested in is also 3.

Now, we can use the slope-intercept form of a line, which is y = mx + b, and substitute the values of m (3), x (2), and y (10) using the point (2, 10) that the line passes through. Then we can solve for b.

Substituting the values into the equation, we have:
10 = 3(2) + b

Simplifying the equation:
10 = 6 + b

To find b, we can subtract 6 from both sides of the equation:
10 - 6 = b
4 = b

Therefore, the value of b is 4.